Try
SELECT ;
SaleDateLast, SPlast, SQlast, ;
SaleDatePrev, SPprev, SQprev, ;
SaleDateRest, SPrest, SQrest ;
FROM ( ;
SELECT Salesman, SaleDate AS SaleDateLast, SUM(pp) AS SPlast, SUM(qq) AS SQlast ;
FROM mytable mt11 ;
WHERE SaleDate =(SELECT MAX(SaleDate) FROM mytable WHERE Salesman = mt11.Salesman) ;
GROUP BY 1,2 ;
) ld ;
JOIN ( ;
SELECT Salesman, SaleDate AS SaleDatePrev, SUM(pp) AS SPprev, SUM(qq) AS SQprev ;
FROM mytable mt21 ;
WHERE SaleDate = (SELECT MAX(SaleDate) FROM mytable mt22;
WHERE Salesman = mt21.Salesman AND SaleDate < (SELECT MAX(SaleDate) FROM mytable WHERE Salesman = mt22.Salesman)) ;
GROUP BY 1,2 ;
) pd ON ld.Salesman = pd.Salesman ;
LEFT JOIN ( ;
SELECT Salesman, {} AS SaleDateRest, SUM(pp) AS SPrest, SUM(qq) AS SQrest ;
FROM mytable mt31 ;
WHERE SaleDate < (SELECT MAX(SaleDate) FROM mytable mt32;
WHERE Salesman = mt31.Salesman AND SaleDate < (SELECT MAX(SaleDate) FROM mytable WHERE Salesman = mt32.Salesman)) ;
GROUP BY 1,2 ;
) rd ON rd.Salesman = pd.Salesman
>So far, that's it. Why? Do you have two approaches?
>
>P.S. thanks for your quick responses!
>
>Yossi
>
>>How many more levels do you have?
>>
>>>
>>>Nothing is ever so simple. I left out another level of complexity, thinking I would be able to do it, but I can't seem to work it out. Here's the next level
>>>
>>>
>>>Salesman Sale Date P Q
>>>Joe 2/4/06 2 7
>>>Joe 2/4/06 3 8
>>>Joe 2/4/06 6 6
>>>Joe 3/4/06 1 5
>>>Joe 5/4/06 4 2
>>>Joe 5/4/06 5 9
>>>Boe 1/4/06 1 5
>>>Boe 2/4/06 2 6
>>>Boe 2/4/06 3 7
>>>Boe 4/4/06 4 8
>>>Boe 4/5/06 5 9
>>>Boe 4/5/06 6 0
>>>Doe 3/4/06 1 7
>>>Doe 6/4/06 2 8
>>>
>>>
>>>I want the following results:
>>>
>>>
>>>sman lst_date Plt qlt date-1 p-1 q-1 date-rest p-rest q-rest
>>>Joe 5/4/06 9 11 3/4/06 1 5 {} 11 21
>>>Boe 4/5/06 11 9 4/4/06 4 8 {} 6 18
>>>Doe 6/4/06 2 8 3/4/06 1 7 NULL NULL NULL
>>>
>>>
>>>'Doe' only has two dates. This can be accomplished with LEFT OUTER JOIN. Otherwise I can't figure out how to handle the salesman level.
>>>
--sb--