>>8 4 1.
>
>No, that is not the solution.
>> I guess the question is when is a son old enough to have a room upstairs.
>
>Any statement about "the oldest son" can be used for the third clue; what the son does is irrelevant. For example, "My oldest son is playing in the park", or "My oldest son is asleep", or "My oldest son likes such-and-such music".
>
>>You didn't say old man which would rule out an answer like 7 4 and 2.
>
>You don't know the age of the second man, but we can be quite sure that he knows his own age.


First of all, it's clear, that man's age is not a simple number, it has multiple dividers. E.g.

x+y+z = 13
x*y*z= Age where could be at least 2 combinations of x*y*z with x+y+z giving 13.

Now, from the remark of the oldest son it's conclusive,
that if 2 sons have the same age, they could not be older than 3rd, e.g.
5+5+3 is not an answer.
3+3+7 would not work, because 63 has only two possible combinations
4+4+5, and the age is 80 also obviously don't work

2+2+9, age is 36, which is 6*6, e.g. 6 and 6 and 1. But since there is only one oldest son, the solution is
2, 2 and 9.

BTW, I solved it without reading the rest of the thread. However, I khew couple of similar puzzles already, so it was not that hard for me to solve it.