>Hi
>You can set the grid back color
>
>Put this in grid Init
>

>nBackColor = this.BackColor
>this.BackColor = thisform.BackColor
>this.SetAll('DynamicBackColor',TRANSFORM(nBackColor),'Column')
>

First off, you don't need the Transform() - the parameter expected is an integer.

Actually, the combination of what you said and what he already got: the dynamic backcolor for columns as in the other replies, and the grid backcolor as you say here. The grid backcolor shows below the last row, if there aren't enough of them to fill the grid.

So, to recap:

this.BackColor = thisform.BackColor
This.SetAll( "DynamicBackColor", ;
   'IIF(!EMPTY(THIS.CURRENTCONTROL.VALUE), 0xFFFFFF, ';
+transform(thisform.backcolor)+')',"Column" )

Though, as Bhavbhuti said, the dynamicBackColor will paint empty cells with form's backcolor. For his original request, just the

this.BackColor = thisform.BackColor

is enough.