General information
Category:
COM/DCOM and OLE Automation
Title:
Excel: Simply open un CSV file
Environment versions
Network:
Windows 2003 Server
Hi,
I want open un csv file and i can't. Anybody know how pass the parameter?.
I'm try with this: oexcel.Workbooks.Open('myfile.csv',,,'xlCSV',,,,,',')
Merci
Matías.
Next
Reply
View the map of this thread
View the map of this thread starting from this message only
View all messages of this thread
View all messages of this thread starting from this message only