>>In that case, why not pass it a 2 column array with all 68 find and replace strings. Then, rewrite your code something like this:
>>

>>FOR nCtr = 1 TO 68
>>   lcBufferOut = STRTRAN(lcBuffer,aStr[nCtr,1],aStr[nCtr,2])
>>ENDFOR
>>

>>I'll bet that would cut your time down to less than 2 minutes!
>>
>>Regards,
>
>I am storing my 68 find & replace in a table, I run it 68 times because I do not want to parse the string for 68 string, so it will end with a much bigger process and I wonder if I will have correct file at the end.

Make sure that you also check the transitions between each Block. To give you an example of what I mean:

lcData = "ABCDEFGHIJKLMNOPQABCDMNKSJHKDABC"
You want to change "MN" into something else. So you split lcData into two:
lcData1 = "ABCDEFGHIJKLM"
lcData2 = "NOPQABCDMNKSJHKDABC"
If you run your process on lcData1 and then on lcData2, you won't catch the first occurence of "MN" since it has been split in two.