lcStr = "Joe"
lcHex = "0x"
FOR i=1 TO LEN(lcStr)
	lcHex = lcHex + RIGHT(TRANSFORM(ASC(SUBSTR(lcStr,i,1)), "@0"),2)
ENDFOR

? lcHex, lcHex = "0x4A6F65"

>That will only work with 1,2,4 or 8 bytes though correct?
>
>>

CTOBIN(retval + CHR(0),"4S") = 0x4A6F6500

>>
>>>Operator/Operand mismatch on my code.
>>>
>>>If retval="Joe" it should equal 0x4A6F65 not "0x004A6F65".
>>>
>>>? TRANSFORM("Joe", "@0") displays "Joe" not 0x4A6F65.
>>>
>>>
>>>>Your code should work. What seems to be a problem? You can try

IF TRANSFORM(retval, "@0") = "4A6F65"
>>>>* or
>>>>retval = "0x004A6F65"
>>>>
>>>>

>>>>
>>>>>Is there any way I can do a comparison from char to hex?
>>>>>
>>>>>

>>>>>retval=FREAD(f,3)
>>>>>if retval=0x4A6F65
>>>>>  do something
>>>>>endif
>>>>>