>Getting the message:
>
>
'MENUINFO' must be created with SELECT...INTO TABLE.>
>on this line:
>
>
>SELECT RecordId, MenuId, ItemType;
> FROM MenuInfo;
> WHERE ParentId == oObject.sRecordId;
> INTO ARRAY aRecords
>
>
>This works fine on 2 development PC's, but on a third development PC, it throws
>this error.
>
>Anyone know what's wrong?
Where you use this SELECT?
Are you sure you didn't have some cursor opened in MenuInfo alias?
Against Stupidity the Gods themselves Contend in Vain - Johann Christoph Friedrich von Schiller
The only thing normal about database guys is their tables.
