Here's what a colleague came up with for the 1's.

INT( SQRT( RTOD( ASIN( SQRT( 1 / ( 1 + 1 ) ) ) ) ) ) = 6

LOL.. He has way to much time on his hands.



>Perfect guys. I knew UT would have solution:)
>Cetin
>
>>If this is allowed, then
>>(1 + 1 + 1)! = 6
>>where ! is the symbol for factorial.
>>:)
>>
>>>the 5's are ((5 squared) + 5) / 5
>>>the 7's are ((7 squared) -7) / 7
>>>
>>>the only ones I can't figure out is the 1's
>>>
>>>
>>>>Hi Cetin,
>>>>Some answer:
>>>>

>>>>Q: 2 2 2 = 6
>>>>   2 + 2 + 2 = 6
>>>>Q: 3 3 3 = 6
>>>>   (3 * 3) - 3 = 6
>>>>Q: 4 4 4 = 6
>>>>   Sqrt(4) + Sqrt(4) + Sqrt(4) = 6
>>>>Q: 6 6 6 = 6
>>>>   6 + 6 - 6 = 6
>>>>Q: 8 8 8 = 6
>>>>   CubeRt(8) + CubeRt(8) + CubeRt(8) = 6
>>>>Q: 9 9 9 = 6
>>>>   (9 + 9) / Sqrt(9) = 6
>>>>

>>>>Are they ok?
>>>>
>>>>
>>>>>They sent me this today via email and I liked it:)
>>>>>Find the math symbols to satisfy results. parentheses, sqrt,cubert, signs, +,-,... etc accepted. ie:
>>>>>Q: 2 2 = 4
>>>>>A: 2 + 2 = 4
>>>>>Q: 4 2 = 1
>>>>>A: Sqrt(4) / 2 = 1
>>>>>Q: 8 2 = 1
>>>>>A: CubeRt(8) / 2 = 1
>>>>>Q: 7 5 = 2
>>>>>A: -7 + 5 = 2
>>>>>
>>>>>Easy. Try with the following:
>>>>>

>>>>>1 1 1 = 6
>>>>>2 2 2 = 6
>>>>>3 3 3 = 6
>>>>>4 4 4 = 6
>>>>>5 5 5 = 6
>>>>>6 6 6 = 6
>>>>>7 7 7 = 6
>>>>>8 8 8 = 6
>>>>>9 9 9 = 6
>>>>>

Cetin
>>>>