Hi Geoff,

>I notice that the toInt() function is missing and assume it converts the number into four byte integer fields.

I'm sorry, here it is:

*========================================================
* Converts a number into a binary string
*========================================================
Function ToInt
LParameter tnValue, tnBytes
    Local lcString, lnByte
    lcString = ""
    For m.lnByte = 1 to m.tnBytes
      lcString = m.lcString + Chr(m.tnValue%256)
      tnValue = Int(m.tnValue/256)
    Endfor
Return m.lcString