John,

"Long" in VB notation is DWORD, occupies 4 consecutive bytes. Use the following procedure to convert any 4 characters from a string buffer to numeric value.

FUNCTION buf2dword(cBuffer)
RETURN Asc(SUBSTR(cBuffer, 1,1)) + ;
	BitLShift(Asc(SUBSTR(cBuffer, 2,1)),  8) +;
	BitLShift(Asc(SUBSTR(cBuffer, 3,1)), 16) +;
	BitLShift(Asc(SUBSTR(cBuffer, 4,1)), 24)

In particular,

nMaxEdgeCrop = buf2dword(SUBSTR(lcDocStatus, 1, 4))
nSpecklesRemoved = buf2dword(SUBSTR(lcDocStatus, 5, 4))
nStandardCkSize = buf2dword(SUBSTR(lcDocStatus, 9, 4))
* ... and so on ...

This is your lcDocStatus

MaxEdgeCrop SpecklesRemoved StandardCkSize ...
1 2 3 4     5 6 7 8         9 a b c
[][][][]    [][][][]        [][][][]
LONG        LONG            LONG