>I have a 5 X 5 grid with each cell having a value of 1 or 0 depending on whether the cell is 'active' or 'inactive'. If 5 cells are active consecutively then it forms a row or column whichever the case may be. Under these conditioins there are 13 possible situations to take into account: 5 rows, 5 columns, 2 diagonals and the four corners plus the center square. I need to find a solution to determine which two are active or three or four for that matter without having to check something like if A = 1 and B =1, if A = 1 and C = 1, and so on....any ideas?
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>Thanks.


You can try to align all zeros and ones in a single row and bitmask the result to test each situations...

HTH :0)