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String question on search screen
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Forum:
Visual FoxPro
Catégorie:
Codage, syntaxe et commandes
Divers
Thread ID:
00110033
Message ID:
00110057
Vues:
17
After looking a bit closer at your code. I see what's happening. If you change it as follows, the error shouldn't occur:
str3 = ""
IF NOT EMPTY(This.Value)
  str3 = "UPPER(Client.Surname) LIKE" + CHR(34) +;
  ALLTRIM(UPPER(This.Value)) + "%" + CHR(34)
ENDIF
This will save you the trouble of having to screen this character out, and allow for a smaller subset to be returned.

hth,
George

Ubi caritas et amor, deus ibi est
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