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Setting the datetime to a time in the future
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To
23/05/2006 06:44:25
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Environment versions
Visual FoxPro:
VFP 8
OS:
Windows XP SP1
Network:
Windows 2000 Server
Database:
Visual FoxPro
Miscellaneous
Thread ID:
01124202
Message ID:
01124212
Views:
15
>>>>>I have a datetime field named scheduled. I would like to replace the contents of the field with the next time the clock is 9 a.m in the morning. So if the datetime were say 23/05/2006 10:36:42
>>>>>I would like to replace the value with 24/05/2006 09:00:00.
>>>>>
>>>>>Can anybody help me please?
>>>>>
>>>>>Thanks
>>>>
>>>>NewDateTime = DateTimeField + (24*60*60)
>>>>? DATETIME(YEAR(NewDateTime), MONTH(NewDateTime), DAY(NewDateTime),9,0,0)
>>>>
>>>>** or
>>>>NewDateTime = TTOD(DateTimeField) + 1
>>>>? DATETIME(YEAR(NewDateTime), MONTH(NewDateTime), DAY(NewDateTime),9,0,0)
>>>>
>>>
>>>I was thinking in the same lines, but then an easier solution "hit me in the head". :-)
>>>?Datetime() -Seconds() + (33*60*60) && 33=24+9
>>
>>Yes, this is great, but If the DateTime value is stored in a field then you couldn't get SECONDS() so easily :-)
>>Imagine that the field contains:
>>01/01/2006 12:33:55, then your method will works only if it is executed at 12:33:55 ;-)
>
>What about this solution?
>?Dtot(ttod(yourfield))+(33*60*60)
GREAT :-)
Against Stupidity the Gods themselves Contend in Vain - Johann Christoph Friedrich von Schiller
The only thing normal about database guys is their tables.
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