OK, a valid address is:
5614 HIGH POINT RD
This works:
declare @cvalue varchar(15)
set @cvalue = '5614'
select * from occ_main where ltrim(rtrim(number))+ltrim(rtrim(st_prefix))+ltrim(rtrim(street))+ltrim
(rtrim(st_type))+ltrim(rtrim(st_suffix))+Ltrim(rtrim(apt_room)) LIKE '%' + ltrim(rtrim(@cvalue)) + '%'
and this works:
declare @cvalue varchar(15)
set @cvalue = 'HIGH'
select * from occ_main where ltrim(rtrim(number))+ltrim(rtrim(st_prefix))+ltrim(rtrim(street))+ltrim(rtrim(st_type))+ltrim(rtrim(st_suffix))+Ltrim(rtrim(apt_room)) LIKE '%' + ltrim(rtrim(@cvalue)) + '%'
and this works:
declare @cvalue varchar(15)
set @cvalue = '5614HIGH'
select * from occ_main where ltrim(rtrim(number))+ltrim(rtrim(st_prefix))+ltrim(rtrim(street))+ltrim(rtrim(st_type))+ltrim(rtrim(st_suffix))+Ltrim(rtrim(apt_room)) LIKE '%' + ltrim(rtrim(@cvalue)) + '%'
but this does not:declare @cvalue varchar(15)
set @cvalue = '5614 HIGH'
select * from occ_main where ltrim(rtrim(number))+ltrim(rtrim(st_prefix))+ltrim(rtrim(street))+ltrim(rtrim(st_type))+ltrim(rtrim(st_suffix))+Ltrim(rtrim(apt_room)) LIKE '%' + ltrim(rtrim(@cvalue)) + '%'
So I guess I have to remove ALL spaces in the value entered to pull matching records. Should've figured that...
(The code was cut from sql sever management studio - not vfp)
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