>Dear All,
>
>I can't figure out how to do the following:
>
>Table Structure
>1. Punch_Date d,
>2. Punch_time t,
>3. time_type n(1) (1=In,2=lunch time begin,3=after lunch,4=out)
>4. Staff_id n(3)
>
>I want to group different time_type by punch_date as follows
>

>ddt = datetime(1900,1,1,0,0,0)
>SELECT punch_date,IIF(time_type=1,punch_time,ddt) as Day_In, IIF(time_type=2,punch_time,ddt) as Lunch_Out,IIF(time_type=3,punch_time,ddt) as Lunch_In, IIF(time_type=4,punch_time,ddt) as Day_Out FROM timecard_log INTO CURSOR timecard_display GROUP BY 1 ORDER BY 1
>

>I couldn't do it?!
>

I tries to guess what do you want.

ddt = datetime(1900,1,1,0,0,0)
SELECT punch_date ;
, MAX(IIF(time_type=1,punch_time,ddt)) as Day_In:
, MAX(IIF(time_type=2,punch_time,ddt)) as Lunch_Out ;
, MAX(IIF(time_type=3,punch_time,ddt)) as Lunch_In ;
, MAX(IIF(time_type=4,punch_time,ddt)) as Day_Out ;
FROM timecard_log INTO CURSOR timecard_display GROUP BY 1 ORDER BY 1

>OR
>
>

>SELECT punch_date,IIF(time_type=1,punch_time,dt) as Day_In, IIF(time_type=2,punch_time,dt) as Lunch_Out,IIF(time_type=3,punch_time,dt) as Lunch_In, IIF(time_type=4,punch_time,dt) as Day_Out FROM timecard_log WHERE exist (SELECT punch_date FROM timecard_log GROUP BY 1) INTO CURSOR timecard_display
>

>This will create 4 records for each day, instead of 1 record for each day