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Mod() function Bug?
Message
From
22/09/2006 11:41:26
Cetin Basoz
Engineerica Inc.
Izmir, Turkey
 
 
To
22/09/2006 10:30:37
Calvin Smith
Wayne Reaves Computer Systems
Macon, Georgia, United States
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Environment versions
Visual FoxPro:
VFP 9 SP1
OS:
Windows XP SP2
Miscellaneous
Thread ID:
01156435
Message ID:
01156501
Views:
18
>The mod command gives stange results when done this way:
>Mod(-13,4). I would expect this to return either 1 or -1 but it returns 3.
>Visual Basic return -1 for this command but Ruby return the same thing as VFP. Can someone explain this to me.... Thanks.

It's a definition by computer languages and in many languages including VFP remainder R is >= 0 and < = n2.
Mod(n1, n2) = n1 - n2[n1/n2] && where [n1/n2] is a floor function
where result should be 3.

Definition could be questioned and further VFP's implementation (ie: why would it return a negative value if it was mod(13,-4) but knowing that for your particular language you could work it.

I'm not an expert in arithmetic definitions:) Just my .02 cents.
Cetin
Çetin Basöz

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