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Removing extra spaces and limiting input to A-Z, 1-0, an
Message
General information
Forum:
Visual FoxPro
Category:
Coding, syntax & commands
Miscellaneous
Thread ID:
01159441
Message ID:
01159486
Views:
17
>>>I am writing an applications where I want to:
>>>
>>>1. remvoe extra spaces between words, i.e. "xxx yyy" becomes "xxx yyy" and that the input is only A-Z and 0-9 (i.e. no specail characters)
>>>
>>>2. the input hast the format "xxx.yyy.ccc.etc) where "xxx", "yyy", "ccc", etc can only A-Z, 0-9, last character cannot be a period, and first character of "xxx", "yyy", "ccc", etc is A-Z.
>>>
>>>My questions are how to best remove the extra spaces and how check that only A-Z and 0-9 are entered.
>>>
>>>TIA
>>
>>Claude,
>>
>>For removing extra spaces, this should do the trick.
>>
>>cString = "xxx  yyy  zzz"
>>cString = STRTRAN(cString,SPACE(2),SPACE(1),1,OCCURS(SPACE(2),cString))
>>
>>Regards,
>
>Actually, this would only work if there was only a double space... not a triple or 4 spaces...
>
>
>cString = "xxx     yyy         zzz"
>do while at( "  ", cString ) > 0
>  cString = strtran( cString, "  ", " " )
>enddo
>
>
>
>As for stripping the other invalid characters you don't want to allow, I would pre-build a string of chars you DONT want, then use CHRTRAN() such as
>
>
>lcInvalid = "`~!@#$%^&*()-_=+{}[]\|;:,<.>/?'" + '"'
>
>cString = "xx@()x]  ]  ] y]yy@(*!$         zzz"
>cString = chrtran( cString, lcInvalid, "" )
>
>the CHRTRAN() will take the string, look for each character found in lcInvalid, and replace it with the character in the same position in parameter 3 (which empty will result in no character and thus cut out of the string).

Thanks, first part works like a charm.

In second part I do NOT want to strip out the in valid characters, I want to check if the are in the string. If string had invalid characters I would tell the user.
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