>Hi Hilmar,
>
>How could I adjust the slant position the for the horizontal lines? What is the mathematical calculation for it?

For the vertical lines, .Width = 0, .Height = (whatever)

For the horizontal lines, .Height = 0, .Width = (whatever)

Or are you referring to something else?

I adjusted the sample code, to print an entire grid, but you must adjust calculations to make the following information varaible: horizontal offset; vertical offset; line spacing; number of lines.

local lnOffset
lnOffset = 50
lnSpacing = 30
for i = 1 to 5
	ThisForm.AddObject("LineVertical" + trans(i), "Line")
	o = eval("ThisForm.LineVertical" + trans(i))
	o.Left = lnOffset + (i - 1) * lnSpacing
	o.Top = 50 && hardcoded in this case
	o.Height = 120
	o.Width = 0
	o.Visible = .T.
next

for i = 1 to 5
	ThisForm.AddObject("LineHorizontal" + trans(i), "Line")
	o = eval("ThisForm.LineHorizontal" + trans(i))
	o.Top = lnOffset + (i - 1) * lnSpacing
	o.Left = 50 && hardcoded in this case
	o.Height = 0
	o.Width = 120
	o.Visible = .T.
next