>>Want to know the leftmost column of the second half of my split grid.
>>
>>Any help ?
>>
>>TIA
>
>This should work
>
>

>local SecondLeftColumnNumber
>
>with m.this.parent.Grid
>
>	do case
>	case empty(.Partition)
>		SecondLeftColumnNumber = 0
>		
>	case .Panel = 1
>		SecondLeftColumnNumber = .LeftColumn
>	
>	otherwise
>		.Panel = 1
>		SecondLeftColumnNumber = .LeftColumn
>		.Panel = 0
>	
>	endcase
>
>endwith
>
>? SecondLeftColumnNumber
>

Hmm, you make it way too easy <g>

Let me test.