>>>Want to know the leftmost column of the second half of my split grid.
>>>
>>>Any help ?
>>>
>>>TIA
>>
>>This should work
>>
>>
>>local SecondLeftColumnNumber
>>
>>with m.this.parent.Grid
>>
>> do case
>> case empty(.Partition)
>> SecondLeftColumnNumber = 0
>>
>> case .Panel = 1
>> SecondLeftColumnNumber = .LeftColumn
>>
>> otherwise
>> .Panel = 1
>> SecondLeftColumnNumber = .LeftColumn
>> .Panel = 0
>>
>> endcase
>>
>>endwith
>>
>>? SecondLeftColumnNumber
>>
>
>Hmm, you make it way too easy <g>
>
>Let me test.
I confess I have tested prior to posting ;-)
Gregory
