>This must be simple ...
>But my mind is stuck.
>
>nRgb=myLabel.forecolor
>nRed=?
>nGreen=?
>nBlue=?
>
>TIA
Right now, I can't find a simple function that just returns red, etc. I hope somebody else can help here.
Otherwise, do the following tests:
? rgb(0,0,1)
? rgb(0,1,0)
? rgb(1,0,0)
It seems that red, blue, and green are stored in three consecutive bytes, so the rgb() function returns red * 256^2 + blue * 256 + green.
From there, you should be able to extract the components with the division and modulus operators.
Difference in opinions hath cost many millions of lives: for instance, whether flesh be bread, or bread be flesh; whether whistling be a vice or a virtue; whether it be better to kiss a post, or throw it into the fire... (from Gulliver's Travels)
