>>Thanks. Found them. Can you tell me why does this cause an error from the command window?

>>od=CREATEOBJECT("MSComDlg.CommonDialog.1")
>>od.AboutBox()  && This works, but...
>>od.Flags= 0x00080000
>>od.filename="*.*"
>>od.ShowOpen()  && ...this causes an OLE error

>>However, if I put the OLE control on a form and run the form, the control works the way it's supposed to.
>
>You have to put control on the form anyway or you'll get licensing error in runtime (mskb #Q192693).

Thanks Sergery. Let me ask one final question... as I'm not sure just how pervasively available is MSComDlg.CommonDialog.

What if I try to open a form with the MSComDlg.CommonDialog control on it, but the machine does not have the control installed. Is that even possible (and still the system be functional?).

I have tried this, and it seems to work:

&& Here, G_CanUseCommonDlg is a public var that starts out at zero.
&& It gets set once in the app as a flag 
&& to indicate that MSComDlg.CommonDialog is available:
IF EMPTY(G_CanUseCommonDlg)
  G_CanUseCommonDlg=1
  LOCAL oOleComDlg
  TRY 
    oOleComDlg=CREATEOBJECT("MSComDlg.CommonDialog.1")
  CATCH 
    G_CanUseCommonDlg=2
  ENDTRY 
  oOleComDlg=.null. 
ENDIF

By doing this, I know if G_CanUseCommonDlg equals 1, that MSComDlg.CommonDialog.1 is available and my app won't throw an error when I open the form upon which the Control is placed. By the way, I set the form's LEFT property to -500 in the Init so the form itself is not visible. Then in its Activate event, I do the code to set up the OleControl and invoke its ShowOpen() method. This seems to work OK.
If G_CanUseCommonDlg equals 2, then I just default to VFP's GetFile() function.

What I don't know is if GetFile() uses MSComDlg.CommonDialog anyway, so that all this checking I'm doing is not necessary.