>>>hi,
>>>thank you for reply,it works
>>>>

>>>>lnNumber = 1235.789
>>>>lcText = TRANSFORM(INT(lnNumber % 1 * 1000))
>>>>

>>>>>
>>
>>Are you sure you always have 3 digits after the point? If you have 2 or more than 3, you would not get the decimal only part, e.g. test with
>>
>>lnNumber = 344.8990034
>>
>>and with lnNumber = 23.44
>>
>For an undertermined number of decimal digits use
>

GETWORDNUM(TRANSFORM(lnnumber),2,'.')

>
>However, this yeilds an empty string (rather than 0) if there are no decimal digits
>
>
>
You can always add VAL() to it :)