Yuri,

Thanks! Now I have the problem that if I do not make it work with the help from you, Hilmar and my co-workers I will have serious confidence problems <g>


>>I am trying to smooth some intersecting lines, and for that I think I need the formula of a circle that is tangent to this two intersecting lines; now, I realize that there will be infinite circles matching this, but I can or would like to <g> specify the tangent points (the points where the circle touches each line), but I am googling for this formula without much success, and all the links that look promising get blocked by the internet filter, so, does anyone know how can I solve this problem?
>>
>>
>>TIA
>>
>>Hugo
>
>Let as assume you know tangent lines and coordinates of tangent points on them:
>y=ax+b, (e,f)
>y=cx+d, (g,h)
>
>Then you draw the perpendicular lines
>y = -x/a + f + e/a
>y = -x/c + h + g/c
>
>Center of the circle is on the intersection of those two perpendicular lines:
>Cx = (h + g/c - f - e/a)* c* c/(a-c)
>Cy = -(Cx)/a + f + e/a
>
>Radius is:
>
>R= sqrt((Cx-e)^2 + (Cy - f)^2)
>
>And formula for circle is:
>
>(y-Cy)^2 + (x - Cx)^2 = R^2
>
>Good Luck