>I can use type for if there is a field in table:
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?type("mytable.myfield")="U"
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>but with vartype
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?vartype("mytable.myfield")="U"
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>is generates variable not found. Isn't that a bug?
Here's what we said in HackFox about this:
"Because VARTYPE() explicitly passes the expression to test as a parameter, it fails if an expression cannot be evaluated, causing an error 12, "Variable not found"—you'll still want to use TYPE() to check if a variable exists."
Tamar