You're welcome. BTW, the max # is lnBase^n - 1, where n is the size of the rersult string.


>This one does all I want. No need to use PADR() anymore. Very nice. The maximum number it supports is 456975. Thanks Sergey.
>
>>Yes, I see the problem. Try (works even for 0)
>>

>>	lcLetters = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
>>	lcCharList = lcLetters
>>	lnBase = LEN(lcCharList)
>>	lcVal = ""
>>	FOR i=1 TO 4
>>		lnRest = (lnVal % lnBase)
>>		lnVal = INT( lnVal / lnBase)
>>		lcVal =  SUBSTR( lcCharList, lnRest + 1 , 1 ) + lcVal
>>	ENDFOR
>>

>>