Hi Moises,

I wrote about a similar problem in my blog, a few weeks ago, and wOOdy reminded me of solving such a problem with regular expressions. REs will do for you, too. For simply checking if the string starts with 2 digits, a slash, 2 digits, a slash, 4 digits you could use something like this:

SET CLASSLIB TO HOME()+ [ffc\_regexp.vcx]
oexp = CREATEOBJECT([_regexp])
oexp.clear
oexp.pattern = "^\d{2}/\d{2}/\d{4}"
* displays 0
?oexp.execute("04.07.2008 1054AC PRESIDENTE EPITACIO - PRESIDENTE EPITACIO/SPConferi")
* displays 1 = valid string
?oexp.execute("04/07/2008 1054AC PRESIDENTE EPITACIO - PRESIDENTE EPITACIO/SPConferi")
* displays 0
?oexp.execute("-04/07/2008- 1054AC PRESIDENTE EPITACIO - PRESIDENTE EPITACIO/SPConferi")
* displays 0
?oexp.execute("04/07/08 1054AC PRESIDENTE EPITACIO - PRESIDENTE EPITACIO/SPConferi")

>The date is in DD/MM/YY format as text below
>
>I already have the line number
>
>I was thinking about something as:
>
>If line contains "2008" or "2009" or "2010", get the the year
>and also contents at its left side and then convert it to date with ctod ()
>
>Can anybody help me with this line, or is there a more smart solution ?
>
>Thanks
>
>
>
>piece of TXT file
>
>**********************************
>
>04/07/2008 10:54AC PRESIDENTE EPITACIO - PRESIDENTE EPITACIO/SPConferido
>
>******************************************************************************