>>>Hi.
>>>I would like to use conditional compilation to have difference method access modifier for unit testing.
>>>
>>>

>>>#if TEST
>>>    public virtual void MyMethod()
>>>#else
>>>    public void MyMethod()
>>>#endif
>>>    {
>>>        // Do Something;
>>>    }
>>>

>>>
>>>I have code as above, I added new constant TEST at solution configuration manager. I changed "constant" among debug, release and TEST. VS 2008 IDE works fine for TEST and debug. However, whenever I change it to release, the method under TEST constant will be used.
>>>
>>>Anyway to make DEBUG/RELEASE to use public void MyMethod() and onyl TEST will use public virtual void MyMethod() ?
>>
>>If I understand correctly what you are trying to do:
>>
>>There is a pre-defined DEBUG constant which should be adequate - just make sure the checkbox in the project 'Build' page is checked for the relevant configurations. You should be able to check whether conditional code will be compiled - if it is not being compiled it will be greyed-out in the IDE. If you really want to use 'TEST' then add it to the 'Conditional Compilation symbols in the 'Debug' configuration of the project properties 'Build' page
>
>
>You can also test for debug mode
>

>if (System.Diagnostics.Debugger.IsAttached)
>{
>     DoSomething()
>}
>else
>{
>     DoSomethingElse()
>}
>

I didn't know that. But now that I do I'm having trouble seeing a use for it.....