Yeah Kamal,
But I don't have a need to keep last two objects, just current is enough for me. Code is doing it, I thought there might be an easier way.
Unfortunately activecontrol applies to form, page, toolbar, _screen not grid. form.activecontrol return the grid, not current active control of it. Thanks.
Cetin
>Hi Cetin,
>
>I would create an object which has an array. This array would store only a max of two object references.
>
>Use your code to get the currently active Object. Then call a method in the array object passing this object as a parameter. This method would push the last object out of the array and put the new one at position one. (LIFO)
>
>This way you get references to your last two objects. You might store into regarding the record to this array too... things like PKey etc.
>
>>Hi folks,
>>Is there an easier way to determine active control in grid ? This code is from beforerowcolchange and already verified it's a rowchange (nColIndex has column value) :
with this
>> if !empty(.columns(nColIndex).dynamiccurrentcontrol)
>> cCurrentControl = ;
>> eval(.columns(nColIndex).dynamiccurrentcontrol)
>> else
>> cCurrentControl = .columns(nColIndex).currentcontrol
>> endif
>> with evaluate(".columns(nColIndex)."+cCurrentcontrol)
>> .value = .value
>> endwith
>>endwith
And next problem. Is there a way to determine last activecolumn in grid.valid, w/o saving it to some property ? MTIA
>>Cetin