>>>>see message#1416401 for a simple way in vfp
>>>
>>>This message points to the original question - which message did you mean?
>>message#1416405
>
>As I said, it doesn't solve the problem we want to solve - we only want to return non-matching values. BTW, my solution was identical to yours (I used inner join), but it doesn't achieve our goal.
>

>	create cursor Schnaps ;
>	(	c1	c(1), ;
>		c2	c(1),; 
>		c3	c(1) ;
>	)
>	
>	insert into Schnaps values ('A', 'a', '1')
>	insert into Schnaps values ('A', 'b', '2')
>	insert into Schnaps values ('A', 'b', '3')
>	insert into Schnaps values ('B', 'c', '4')
>	insert into Schnaps values ('B', 'c', '4')
>	insert into Schnaps values ('B', 'd', '4') && Need to return this - no match
>	insert into Schnaps values ('B', 'e', '4') && added
>	insert into Schnaps values ('B', 'e', '4') && added
>	insert into Schnaps values ('B', 'f', '4') && added  && Need to return this - no match
>	insert into Schnaps values ('A', 'b', '3')
>	
>*!*		select T.* from Schnaps T INNER JOIN ;
>*!*		(SELECT c3, MIN(c1) as c1_min,MAX(c1) as c1_max, ;
>*!*		MIN(c2) as c2_min, MAX(c2) as c2_max FROM Schnaps X group by 1 ;
>*!*		HAVING COUNT(distinct(c1+c2)) > 1) X ON T.c3= X.c3 
>	
>	select S.* ;
>		from Schnaps S, ;
>			( ;
>				select c3 ;
>					from Schnaps ;
>					group by  1 ;
>					having ( count( distinct c1 + c2 ) > 1) ;
>			) AA ;
>			where	( S.c3 == AA.c3 )
>

Look, you're turning the original problem into something else

I have said ' I have no time for this'
I repeat: I won't be answering to you any more in this thread