select int_id, street1, street2, count(int_id) as crashes ;
  , SUM( IIF(INJURY_SEV=1, 1, 0) ) AS sev1  ;
  ...
  , SUM( IIF(INJURY_SEV=6, 1, 0) ) AS sev6  ;

>I am still trying to get the SQL group by clause down. Can someone help me with this?
>The table contains a record for each accident at intersections in the city. Fields are an intersection identifier INT_ID, the 2 cross streets STREET1 and STREET2, injury severity INJURY_SEV coded 1 through 6. I want to obtain 1 record per intersection containing the total number of crashes at the intersection plus the total number for each of the 6 severity codes. This works for the total but I can't figure out how to add the six severity codes.
>
>

>select int_id, street1, street2, count(int_id) as crashes;
>	from crash1 ;
>	group by int_id, street1, street2 ;
>	order by crashes desc, int_id
>

>
>Thanks