function Secs2cTime lparameters ttEnd, ttStart lnSecs = ttEnd - ttStart lnHours = int(lnSecs/3600) lnMins = int(lnSecs%3600/60) && Secs LTE 59 important ? return padl(lnHours,2,"0")+":"+padl(lnMins,2,"0") * Another approach - Similar to Ed's function cDiffTime lparameters ttEnd, ttStart cTime1 = ttoc({1/1/1998 00:00}+(ttEnd - ttStart),2) && secs and date setting && determine if secs included lnHours = floor((ttEnd - ttStart)/86400)*24+val(substr(cTime1,1,2)) return ltrim(str(lnHours))+substr(cTime1,3)Cetin