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À
19/11/2009 10:35:56
Information générale
Forum:
Visual FoxPro
Catégorie:
Programmation Orientée Object
Versions des environnements
Visual FoxPro:
VFP 9 SP2
OS:
Windows XP SP2
Network:
Windows 2003 Server
Database:
Visual FoxPro
Divers
Thread ID:
01435599
Message ID:
01435612
Vues:
91
This message has been marked as the solution to the initial question of the thread.
>Hi!
>
>On my form I have grid. I add spinner to grid column in grid's init event:
>
>
>
>With This
>	.Column4.AddObject("spnQuantity", "Spinner")
>	.Column4.CurrentControl = "spnQuantity"
>	.Column4.spnQuantity.Visible = .T.
>	.Column4.spnQuantity.BorderStyle = 0
>	.Column4.spnQuantity.SpecialEffect = 1
>	.Column4.spnQuantity.Margin = 0
>	.Column4.spnQuantity.SpinnerLowValue = 0

                   BINDEVENT(.Column4.spnQuantity,'InteractiveChange', Thisform,'ChangeButtonStatus')

>EndWith
>
>
>
>Now I need to change status of some buttons on form. How to refer to spinner's InteractiveChange event?
>
>Thanks!

See the line I added to your code.
If it's not broken, fix it until it is.


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