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A math question
Message
De
21/01/2010 08:19:56
Hilmar Zonneveld
Independent Consultant
Cochabamba, Bolivie
 
 
À
21/01/2010 08:12:48
Lutz Scheffler
Lutz Scheffler Software Ingenieurbüro
Dresden, Allemagne
Information générale
Forum:
Games
Catégorie:
Mathématique
Titre:
Divers
Thread ID:
01445159
Message ID:
01445168
Vues:
31
>F(x/y) = log(x/y)
>F(x) = log(x)
>F(y) = -log(y)
>
>e.g.
>log(x/y) = log(x)+(-log(y)) = log(x)-log(y)
>
>x=100
>y=10
>
>(for each y=x*10)
>
>log(x/y)=log(10)=1
>log(10000) = 4
>
>works perfect.

If f(x) = log x, then f(y) would be log(y). It must be the same function for both cases, otherwise they would use different letters. Only the argument should be replaced, e.g., if f(x) = log x, then f(10) = log 10, f(10000) = log 10000, and f(y) = log y.
Difference in opinions hath cost many millions of lives: for instance, whether flesh be bread, or bread be flesh; whether whistling be a vice or a virtue; whether it be better to kiss a post, or throw it into the fire... (from Gulliver's Travels)
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