>>>>>is there a quick way to inspect a text document and change all [1] to [01] and all [2] to [02] etc something along the lines of what i have set up below (which doesn't work) - or should i be looking at another approach altogether?
>>>>>

>>>>>cFile = Filetostr("C:\mytext.txt") 
>>>>>
>>>>>cFile = Strtran(cFile,Chr(202),"E") && using this code i can change only one character at a time
>>>>>
>>>>>cFile = strtran(cFile,"[5]","[05]")  && can i use the same approach for character string - perhaps using chrtran??
>>>>>

>>>>
>>>>If:
>>>>
>>>>- you don't use the "[" character anywhere else
>>>>- you always want to put a "0" after it, no matter the length of the number between "[" and "]"
>>>>
>>>>then you could just use STRTRAN() to replace each "[" with "[0".
>>>
>>>unfortunately al this is not the case - i have numbers 01-99 and this only affects the first 9 numbers in which case i want to see 01 and not 1 to maintain the character count. past 09 i'm fine.
>>>
>>>abcdefg [01] = is what i need
>>>as opposed to submitted data which reads # abcdefg [1]
>>
>>Well, in that case you could just brute-force it in 10 lines of code, no RegEx needed, maintainable in pure VFP:
>>

>>cFile = strtran(cFile,"[0]","[00]") && if you need to handle [0]
>>cFile = strtran(cFile,"[1]","[01]")
>>cFile = strtran(cFile,"[2]","[02]")
>>cFile = strtran(cFile,"[3]","[03]")
>>cFile = strtran(cFile,"[4]","[04]")
>>cFile = strtran(cFile,"[5]","[05]")
>>cFile = strtran(cFile,"[6]","[06]")
>>cFile = strtran(cFile,"[7]","[07]")
>>cFile = strtran(cFile,"[8]","[08]")
>>cFile = strtran(cFile,"[9]","[09]")
>>
>>* or, if you wanted to do it in "one line of code", you could nest the above calls < eg >
>>

>>Some people might pooh-pooh brute-force solutions, but they have their place.
>
>i was trying to go that route Al - see my example above - but unfortunately this method does not seem to be working here and i suspect it is because the strtran can only be applied to a singel character change not multiple characters. thanks for the try. k

I saw your original example, I copied/pasted it for mine :)

I just did a test, multi-character replacement works fine for me:

lcTest = "aa [1] bb [2] cc [3] aa [1] bb [2] cc [3]"
lcChanged = STRTRAN( lcTest, "[1]", "[01]" )
lcChanged = STRTRAN( lcChanged, "[2]", "[02]" )
lcChanged = STRTRAN( lcChanged, "[3]", "[03]" )
?lcChanged