>insert into curOrdertype values(3,"nbrthree") >>and
>insert into curClient values(4,"George") >>this will give me a 0.00 for all orders ;(
>>SELECT curClient.cName, CAST(NVL(curOrder.nAmount, 0.00) AS N(8,2)) AS Amount, curOrdertype.cType ; >> FROM curOrdertype, curClient ; >> LEFT JOIN curOrder ON curOrder.iOrdertype = curOrdertype.ID ; >> AND curOrder.iClient = curClient.ID ; >> ORDER BY curClient.ID, curOrdertype.ID >>>>