>Hi,
>
>I need to construct a cursor with all possible solutions (no not a carthesian) :
>
>

>CREATE CURSOR curOrder (id i ,iClient i, nAmount n(8,2), iOrderType i ) 
>INSERT INTO curOrder VALUES( 1, 1, 100.00, 1)
>INSERT INTO curOrder VALUES( 2, 2, 110.00, 1)
>INSERT INTO curOrder VALUES( 3, 2, 120.00, 2)
>
>
>CREATE CURSOR curOrdertype (ID i, cType c(10))
>INSERT INTO curOrdertype values(1,"import")
>INSERT into curOrdertype VALUES(2,"export")
>
>CREATE CURSOR Client (ID i, cName c(10))
>INSERT INTO Client values(1,"john")
>INSERT INTO Client values(2,"pete")
>INSERT INTO Client values(3,"eva")
>

>
>My target is:
>
>John, 100.00, import
>John, 0.00, export
>Pete, 110.00, import
>Pete, 120.00, export
>Eva, 0.00, import
>Eva, 0.00, export
>
>The basic statement :
>

>SELECT curOrdertype.cType, curOrder.iClient, curOrder.nAmount, curClient.cName ;
>FROM curOrdertype ;
>FULL JOIN curOrder ON curOrder.iOrdertype = curOrdertype.ID ;
>FULL JOIN curClient ON curClient.ID = curOrder.iClient
>

>will not show the 0.00 order amount lines, I dont seem to be able to construct a correct union , anyone with a good idea?
>
>Thanks,
>
>Koen

CREATE CURSOR curOrder (id i ,iClient i, nAmount n(8,2), iOrderType i ) 
INSERT INTO curOrder VALUES( 1, 1, 100.00, 1)
INSERT INTO curOrder VALUES( 2, 2, 110.00, 1)
INSERT INTO curOrder VALUES( 3, 2, 120.00, 2)


CREATE CURSOR curOrdertype (ID i, cType c(10))
INSERT INTO curOrdertype values(1,"import")
INSERT into curOrdertype VALUES(2,"export")

CREATE CURSOR curClient (ID i, cName c(10))
INSERT INTO curClient values(1,"john")
INSERT INTO curClient values(2,"pete")
INSERT INTO curClient values(3,"eva")

SELECT curOrdertype.cType;
	, NVL(curOrder.nAmount,0) nAmount;
	, curClient.ID iClient;
	, curClient.cName ;
	FROM curClient ;
		 JOIN curOrdertype ON .T.;
	LEFT JOIN curOrder ON curOrder.iOrdertype = curOrdertype.ID AND curClient.ID = curOrder.iClient;
	ORDER BY 3,4