>How do you determine the number of records (rows containing data) in a column? > >Thanks, >Robert Wright > >Oops ... I knew I had done this before but just couldn't remember how ... I found the answer in some old code: > >lnRecordCnt = VAL(STRTRAN(oExcel.RANGE("A65536").END(XLUP).Address,'$A$','')) > > >Robert