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2.0000 = 1 Huh???
Message
Information générale
Forum:
Visual FoxPro
Catégorie:
Codage, syntaxe et commandes
Versions des environnements
Visual FoxPro:
VFP 8 SP1
OS:
Windows XP SP2
Network:
Windows 2008 Server
Database:
Visual FoxPro
Application:
Desktop
Divers
Thread ID:
01484194
Message ID:
01484200
Vues:
146
This message has been marked as the solution to the initial question of the thread.
Result is not exactly 2.0 but a floating point number close to it
? INT(ROUND(lnElapsedMinutes,0))
>
>Something weird here....
>
>I was adding some new code to an old part of the POS program here.....
>
>Here is the new code...
>
>
>ldtBegin = DATETIME(YEAR(mH_BDate),MONTH(mH_BDate),DAY(mH_BDate),mBeg_Hr,mBeg_Min,0)
>ldtEnd   = DATETIME(YEAR(mH_EDate),MONTH(mH_EDate),DAY(mH_EDate),mEnd_Hr,mEnd_Min,0)
>
>lnElapsedSeconds = ldtEnd - ldtBegin
>
>*Convert to minutes
>lnElapsedMinutes = INT(lnElapsedSeconds / 60)
>
>
>And as I traced it, here are the results....
>
>lnElapsedSeconds = 120
>
>ok
>
>lnElapsedMinutes / 60 = 2.0000
>
>finally....
>
>INT(lnElapsedMinutes ) = 1
>
>OK... I was expecting 2 .... so.... where did I go wrong?
>
>Thanks!
--sb--
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