>>>How to find the 10 multiple immediately higher then a number.
>>>
>>>e.g.
>>>
>>>2 ---------- 10
>>>15----------20
>>>17----------20
>>>21----------30
>>>41----------50
>>>
>>>Seems simple but I cannot imagine a function to do it.
>>
>>Just for variety (and assuming no negative values):

x -MOD(x,10)+10

Works with values other than 10 as well :-}
>
>Another option, that does work with negative numbers, is:
>

>ceiling(x/10)*10
>

Hilmar, I tried your method with x = 80 and it returned 80 instead of the correct answer 90 ?