What error you get after calling method OpenInternet()?
?this.Ftp.GetExtendedErrorCode(),this.Ftp.GetExtendedErrorMsg()

MartinaJ


>here is lines of code :
>

>If !(Type("this.ftp") == 'O' and !IsNull(this.ftp))
>	this.Ftp = createobject('ftp_service')
>	this.ftp.cProxyPort = zProxyPort && 3128
>	this.ftp.cProxyHost	= zProxyIp && 10.4.50.10
>	If !Empty(zProxyip)
>		this.ftp.cProxyProtocol = zProxyProtocol  && "http"
>	Else
>		this.ftp.cproxyProtocol = ''	
>	EndIf 	
>EndIf 
>
>this.statoConn = this.Ftp.OpenInternet(zUserFtp, zPwFtp, zFtpAddress, zFtpPort)
>
>

>
>
>
>>How you set cProxy???? properties on FTP object?
>>
>>MartinaJ
>>
>>
>>>I tried but without success :(
>>>
>>>I installed a filezilla ftp client on that pc and it works with these settings :
>>>
>>>proxy FTP = none
>>>
>>>Generic Proxy : connection method = http/1.1
>>> host proxy = 10.4.50.10
>>> proxy port = 3128
>>>
>>>What should I do to make my program working ?
>>>
>>>thanks again
>>>
>>>
>>>>Hi Alessio,
>>>>
>>>>Check cProxyProtocol property in help...
>>>>
>>>>MartinaJ
>>>>
>>>>>Hi Michel, sorry for disturbing you, but I don't know what to do for connecting to a ftp server from a under proxy client.
>>>>>
>>>>>I'm using the Robert Abram ftp service V.2.0.9 and it works fine without proxy but I don't know what to do for bypassing the proxy
>>>>>
>>>>>actually I call the openinternet function in this way
>>>>>
>>>>>

>>>>>	this.Ftp = createobject('ftp_service')
>>>>>	this.ftp.cProxyPort      = zProxyPort  && 3128
>>>>>	this.ftp.cProxyHost	= zProxyIp   &&  10.4.50.10     
>>>>>
>>>>>       this.connStatus = this.Ftp.OpenInternet(zUserFtp, zPwFtp, zFtpAddress, zFtpPort)
>>>>>

>>>>>
>>>>>well, i can't connect
>>>>>
>>>>>what should I do to make it working ?
>>>>>
>>>>>Thank you so much
>>>>>Alessio