In addition - if the # in the format converts leading zeroes to spaces, the pattern has to be adjusted to match the leading spaces

@"^ *-?\d+(\.\d{2})?$"

>The d in the regex expr has to escaped
>
>And come to think of it - the dot has to be escaped as well otherwise it would match any character
>
>in C#, I would write
>

>new System.Text.RegularExpressions.Regex(@"^-?\d+(\.\d{2})?$", System.Text.RegularExpressions.RegexOptions.None);
>
>

>
>>Hi,
>>
>>I'm trying to run some code I found on the net for use in an SSRS report. Here is the relevant bit:
>>
>>

Shared expr As New  _
>>System.Text.RegularExpressions.Regex("^-?d+(.d{2})?$", _
>>System.Text.RegularExpressions.RegexOptions.None)
>>
>>Public Function ExpandPrice(ByVal Price As Double, Optional ByVal pSeparator As String = ".") As String
>>
>>    Dim pPrice As String
>>    pPrice = FORMAT(Price, "##############.00")
>>
>>    Dim temp As New System.Text.StringBuilder()
>>    If Not expr.IsMatch(pPrice) Then
>>        ' temp.Append(pPrice) or whatever you want to do here 
>>        temp.Append("we got here")
>>    Else

>>
>>What I am getting back from this function is the text "we got here" when I pass 208.26 (or any other number for that matter) in. I don't know VB very well, nor the Regular Expressions stuff so would appreciate if anyone could point out why the passed in number is failing the IsMatch check.
>>
>>Thanks