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Getting from distance for geography coordinates
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À
22/11/2011 11:40:52
Information générale
Forum:
Microsoft SQL Server
Catégorie:
Syntaxe SQL
Versions des environnements
SQL Server:
SQL Server 2008
Application:
Web
Divers
Thread ID:
01529492
Message ID:
01529531
Vues:
20
>>
>>;with cte as (SELECT Client.Numero, 3958.75586574*ACOS(
>> CASE WHEN SIN(@Latitude3/57.2957795130823)*SIN(Client.Latitude/57.2957795130823)+
>>           COS(@Latitude4/57.2957795130823)*COS(Client.Latitude/57.2957795130823)*
>>           COS(Client.Longitude/57.2957795130823-@Longitude3/57.2957795130823)<-1
>>           THEN -1
>>      WHEN SIN(@Latitude5/57.2957795130823)*SIN(Client.Latitude/57.2957795130823)+
>>           COS(@Latitude6/57.2957795130823)*COS(Client.Latitude/57.2957795130823)*
>>           COS(Client.Longitude/57.2957795130823-@Longitude4/57.2957795130823)>1
>>           THEN 1
>>      ELSE SIN(@Latitude7/57.2957795130823)*SIN(Client.Latitude/57.2957795130823)+
>>           COS(@Latitude8/57.2957795130823)*COS(Client.Latitude/57.2957795130823)*
>>           COS(Client.Longitude/57.2957795130823-@Longitude5/57.2957795130823)
>> END) as Distance
>>
>>FROM dbo.Client
>>
>>
>> WHERE (Client.Latitude>=@Latitude-250/111.0 AND Client.Latitude<=@Latitude2+250/111.0) AND
>>(Client.Longitude>=@Longitude-250/111.0 AND Client.Longitude<=@Longitude2+250/111.0) )
>>
>>select * from cte where Distance <=250
>
>Thanks, I am always trying to avoid that syntax as it makes it more difficult to migrate to another backend.

Instead of using CTE use derived table.
If it's not broken, fix it until it is.


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