I updated my answer, feel free to ask again if you don't understand the concept.

>I believe you just answered my questions. So, first, thank you! The only thing I am not clear is how do you convert the stored sum into the choices? For example, if the stored number is 12. How would you convert this 12 into 4 and 8?
>
>>Why not use binary values?
>>
>>Choice 1 ---- 1
>>Choice 2 ---- 2
>>Choice 3 ---- 4
>>Choice 4 ---- 8
>>Choice 5 ---- 16
>>Choice 6 ---- 32
>>
>>Sum the values to store them. You can then easily retrieve which choices were selected.
>>
>>lnX = the sum
>>
>>To check if Choice 1 was selected : ?Bittest(lnX,0)
>>To check if Choice 2 was selected : ?Bittest(lnX,1)
>>To check if Choice 3 was selected : ?Bittest(lnX,2)
>>Note that the value after lnX is one lower than expected, since Bittest() is zero based.
>>
>>>Hi,
>>>
>>>I am looking for a formula (if possible) to convert a multiple choice(s) into a number. Kind of like the VFP Anchor property bit value works. Here is my example:
>>>Choice 1 ---- ##
>>>Choice 2 ---- ##
>>>Choice 3 ---- ##
>>>Choice 4 ---- ##
>>>Choice 5 ---- ##
>>>Choice 6 ---- ##
>>>
>>>Each choice above would have a number (##). Then when a user checks any number of choices (from 1 to 6), the "total" number is calculated. This "total" number should be unique for any combination of the selected choices. So that this number can be used (in reverse) to see what choices it represent.
>>>Any suggestions?