>>>>If I try
>>>>

>>>>Int16 closeDrawers = 2;
>>>>
>>>>if (closeDrawers.InList(2,4))
>>>>
>>>>

>>>>
>>>>I get an error about Short don't have InList implemented. I bypassed it by using Int32 instead but just wondering what was wrong in the above.
>>>
>>>Remind us how you are currently implementing InList() ....
>>
>>

>> public static bool InList<T>(this T s, params T[] list)
>>        {
>>            return list.Contains(s);
>>        }

>
>At first sight
>
>closeDrawers is an Int16
>
>The generic class above, for int 16 , will compile into
>>

>> public static bool InList (this Int16 s, params Int16[] list)
>>        {
>>            return list.Contains(s);
>>        }

>
>Which means it is expecting Int16 as parameters
>
>Either of following solutions - not tested
>
>(1) declare closeDrawers as Int
>
>(2) cast closeDrawers to Int
>

>if (((Int)closeDrawers).InList(2,4))
>

>
>(3) pass shorts to Inlist
>

>>>>if (closeDrawers.InList(  (int16)2,  (int16)4))
>

I picked up the simplest solution of declaring closeDrawers as Int32 (although in the database it's tinyint). I think C# "thinks" that 2 and 4 are Int32 constants and this is why I'm getting an error. I probably could use your solution #3 also. Wondering if that's important in any way?

Thanks.