>If a method is created like below, how does ":this()" at the end change the result? why can it be needed at all?
>

> public Product(int new_id, short product_name, string product_type) : this() 
>

>Thanks


The this() at the end is executing the (code of the) parameterless constructor before the code of public Product(int new_id, short product_name, string product_type)

Example - execute this - you will see that Prop1 is set before Prop2

	public static class qqq
	{
		static void Main()
		{
			A a = new A(23);
			Console.ReadLine();
		}
	}

	class A
	{
		int Prop1;
		int Prop2;

		public A()
		{
			Prop1 = 1;
			Console.WriteLine("prop1");
		}

		public A(int x)
			: this()
		{
			Prop2 = x;
			Console.WriteLine("prop2");
		}
	}