>I need to do a SQL command which will search on a field which has 15 characters but the user will enter the last six digits only. So, basically, the first 9 characters are not entered and I must find the record matching the last six digits. I usually do the opposite with the % character at the end combined with a LIKE. Anyone has an example on this type of search?
Well, you can use % in front or use
select .. from myTable where RIGHT(Column,6) = @Last6
May perform marginally better
select .. from myTable where Column LIKE '%' + @Last6
If it's not broken, fix it until it is.
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