>>>Hi everybody,
>>>
>>>We're passing XML like this
>>>
>>>

>>>"<tcactionlist><BACKCOLOR>16496253</BACKCOLOR><BarIndex>1</BarIndex>
>>><BarKeyID>YEM918Z</BarKeyID><BARTYPE></BARTYPE><Base_ID>0</Base_ID>
>>><Booking_ID></Booking_ID><category>SNOWBOARD</category><CLIP_LOC></CLIP_LOC>
>>><CLIP_SP></CLIP_SP><Clipboard></Clipboard><CRITERIA1>0</CRITERIA1><CRITERIA2>.F.</CRITERIA2><CRITERIA3>.F.</CRITERIA3>
>>><CRITERIA4>0</CRITERIA4><CRITERIA5>0</CRITERIA5><CRITERIA6>0</CRITERIA6>
>>><CRITERIA7>2</CRITERIA7><Date_time>04/30/2013 16:59:00</Date_time></tcactionlist>"
>>>

>>>
>>>Basically, it's a table's row. We don't necessary pass every column with value.
>>
>>But you do have an XML element for each column ? And the values, where supplied, are quaranteed to be the correct type ?
>>
>I am not sure I have the element for each column. The sample I found is not completely written (I guess it's because we don't write the whole invoke string). The sample I found was truncated at date_time value.
>
>BTW, this is what I tried in the meantime and quick test seemed to work
>
>

>string xml = @"<b_sched><BACKCOLOR>16496253</BACKCOLOR><BarIndex>1</BarIndex>
><BarKeyID>YEM918Z</BarKeyID><BARTYPE></BARTYPE><Base_ID>0</Base_ID>
><Booking_ID></Booking_ID><category>SNOWBOARD</category><CLIP_LOC></CLIP_LOC><CLIP_SP></CLIP_SP>
><Clipboard></Clipboard><CRITERIA1>0</CRITERIA1><CRITERIA2>false</CRITERIA2><CRITERIA3>false</CRITERIA3>
><CRITERIA4>0</CRITERIA4><CRITERIA5>0</CRITERIA5><CRITERIA6>0</CRITERIA6><CRITERIA7>2</CRITERIA7>
><Date_time>04/30/2013 16:59:00</Date_time></b_sched>";
>			DataSet ds = new DataSet();
>			ds.ReadXml(new XmlTextReader(new StringReader(xml)));
>			
>foreach (DataRow row in ds.Tables[0].Rows)
>{
>	foreach (DataColumn column in ds.Tables[0].Columns)
>	{
>		Console.WriteLine (column.ColumnName + ":  " + row[column.ColumnName].ToString());	
>	}
>}			

Don't think that will work if you want to add the row to an existing table since the Row generated from the XML would not be the same as the row created by DataTable.NewRow().