>>It is possible to keep trying. I would change the code this way then
>>

>>llReTry = .f.
>>lnAttempts = 0
>>try
>>
>>   code that may fail
>>catch to loError
>>   if loError.ErrorNo = 2027
>>       llReTry = .t.
>>  endif
>>endtry
>>   
>>
>>do while m.llReTry = .t. and m.lnAttempts <= 10
>>     lnAttempts = m.lnAttempts + 1
>>   
>>    try
>>
>>   code that may fail
>>   llReTry = .f.
>>catch to loError
>>   if loError.ErrorNo = 2027
>>       llReTry = .t.
>>  endif
>>endtry
>>
>>enddo
>>

>
>
>Thank you Very-Very Much. I will Study it more and try to incorporate it based on all the guidance you have given and will let you know tomorrow that how it works.
>Thanks a lot again.

Good luck!