>>Lets divide the pattern in 6 groups:
>>Group 1: [0-9]+;
>>Any quantity of numbers followed by ; and a space
>>Group 2: [0-9]+
>>Any quantity of numbers followed by a space
>>Group 3: [0-9]+
>>Any quantity of numbers followed by a space
>>Group 4: SCHEMA -
>>Exactly the text SCHEMA -
>>Group 5: here's the problem...
>>Anything unless exactly the text information-schema or anything that doesn't start with pg_
>>Group 6: [a-zA-Z]+
>>Any quantity of characters.
>
>
>>Lets divide the pattern in 6 groups:
>>Group 1: [0-9]+;
>>Any quantity of numbers followed by ; and a space
>>Group 2: [0-9]+
>>Any quantity of numbers followed by a space
>>Group 3: [0-9]+
>>Any quantity of numbers followed by a space
>>Group 4: SCHEMA -
>>Exactly the text SCHEMA -
>>Group 5: here's the problem...
>>Anything unless exactly the text information-schema or anything that doesn't start with pg_
>>Group 6: [a-zA-Z]+
>>Any quantity of characters.
>
>For readability, I have
>- used [ ] to represent the space char
>- put the different groups within parentheses
>- used p5 for group 5
>
>

>	local regexObj
>	regexObj = createobject('VBScript.RegExp')
>	regexObj.Global = .f.
>	regexObj.IgnoreCase = .f.
>	regexObj.MultiLine = .f.
>	
>	local pattern, p5
>	pattern = '^(\d+;[ ])(\d+[ ])(\d+[ ])(SCHEMA[ ]-[ ])(%%p5%%)([a-zA-Z]+)$'
>	p5 = '(?!information-schema[ ])(?!pg_)[\w-]+[ ]'
>	pattern = strtran(m.pattern, '%%p5%%', m.p5)
>	regexObj.Pattern = m.pattern
>	
>	local samples
>	text to samples noshow pretext 7
>		8; 2615 1490850 SCHEMA - e9999 postgres
>		8; 2615 1490850 SCHEMA - pg_catalog postgres
>		8; 2615 1490850 SCHEMA - pg_temp postgres
>		8; 2615 1490850 SCHEMA - information-schema postgres
>		8; 2615 1490850 SCHEMA - information-test postgres
>		8; 2615 1490850 SCHEMA - information postgres
>		8; 2615 1490850 SCHEMA - schema postgres
>		8; 2615 1490850 SCHEMA - myinformation-schema postgres
>		8; 2615 1490850 SCHEMA - information-schemas postgres
>	endtext
>	
>	local aa[1], naa, i, s
>	naa = alines(aa, m.samples)
>	
>	for i = 1 to m.naa
>		s = m.aa[m.i]
>		
>		?m.i, m.regexObj.Test(m.s), m.s
>	endfor
>

Ha. I'd forgotten about the VBScript option - Regex is back in the picture ! :-}

I'm going to be dealing with strings (about 150 words long, liberally sprinkled with brackets and commas). I need to scan this text looking for mainly words (but occasionally phrases) contained in a lookup table and, when a matching word/phrase is found, replace it with the replacement text in the lookup. We're estimating that the table will have ~200 entries. A word or phrase may appear multiple times in the text. Won't be starting for a few days - got other stuff to finish up - but I may get back to you on a new thread. Thx.